Given a set of distinct integers, S, return all possible subsets.
Note:
For
example,
If S = [1,2,3],
a solution is:
[ [3], [1], [2], [1,2,3], [1,3], [2,3], [1,2], [] ]
Code:
|
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22 |
class
Solution {public: void
findSub(vector<int> &S, int
&n, int
level, vector<int> &buf, vector<vector<int>> &res){ if(buf.size()==n){ res.push_back(buf); return; } for(int
i=level;i<S.size();i++){ buf.push_back(S[i]); findSub(S,n,i+1,buf,res); buf.pop_back(); } } vector<vector<int> > subsets(vector<int> &S) { vector<vector<int>> res; vector<int> buf; sort(S.begin(),S.end()); for(int
i=0;i<=S.size();i++) findSub(S,i,0,buf,res); return
res; }}; |
原文:http://www.cnblogs.com/winscoder/p/3535422.html