Given a binary tree, determine if it is height-balanced.
For this problem, a height-balanced binary tree is defined as a binary tree in which the depth of the two subtrees of every node never differ by more than 1.
判断一棵树是否是平衡二叉树
利用高度的答案,递归求解。
/** * Definition for a binary tree node. * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public boolean isBalanced(TreeNode root) { if( root == null) return true; int left = maxDepth(root.left); int right = maxDepth(root.right); if( left - right > 1 || right - left > 1) return false; return isBalanced(root.left)&&isBalanced(root.right); } public int maxDepth(TreeNode root) { if( root == null ) return 0; if( root.left == null && root.right == null) return 1; if( root.left == null) return maxDepth(root.right)+1; if( root.right == null) return maxDepth(root.left)+1; return Math.max(maxDepth(root.left),maxDepth(root.right))+1;} }
leetcode 110 Balanced Binary Tree ----- java
原文:http://www.cnblogs.com/xiaoba1203/p/6011207.html