Given n non-negative integers a1, a2, ..., an, where each represents a point at coordinate (i, ai). n vertical lines are drawn such that the two endpoints of line i is at (i, ai) and (i, 0). Find two lines, which together with x-axis forms a container, such that the container contains the most water.
Note: You may not slant the container.
给定一个数组，每个索引代表一面障碍物，索引位的值代表障碍物的高度；从数组中选取两个障碍物，要求两个障碍物和底构成的槽能装水的量最大。
class Solution {
public:
int maxArea(vector<int> &height) {
int result=0;
int size=height.size();
if(size==0)return result;
int phead=0;
int ptail=size-1;
while(phead<ptail){
//计算当前盛水量
int shorter=min(height[phead], height[ptail]);
int volumn=shorter*(ptail-phead);
if(volumn>result)result=volumn;
//搜索新的可能的水槽边界
if(height[phead]<height[ptail]){
while(phead<ptail && height[phead]<=shorter)phead++;
}
else{
while(phead<ptail && height[ptail]<=shorter)ptail--;
}
}
return result;
}
};LeetCode 011 Container With Most Water,布布扣,bubuko.com
LeetCode 011 Container With Most Water
原文：http://blog.csdn.net/harryhuang1990/article/details/25918893