1 使用HttpServletResponse来处理--不需要配置解析器
@Controller public class AjaxController { @RequestMapping("/ajax") public void ajax(String name,HttpServletResponse resp) throws IOException{ if ("sgcc".equals(name)) { resp.getWriter().print("true"); System.out.println("true"); }else { resp.getWriter().print("false"); } } }
前台
<%@ page language="java" import="java.util.*" pageEncoding="UTF-8"%> <% String path = request.getContextPath(); String basePath = request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+path+"/"; %> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <base href="<%=basePath%>"> <title>My JSP ‘index.jsp‘ starting page</title> <meta http-equiv="pragma" content="no-cache"> <meta http-equiv="cache-control" content="no-cache"> <meta http-equiv="expires" content="0"> <meta http-equiv="keywords" content="keyword1,keyword2,keyword3"> <meta http-equiv="description" content="This is my page"> <!-- <link rel="stylesheet" type="text/css" href="styles.css"> --> <script type="text/javascript" src="jquery-1.8.3-min.js"></script> </head> <body> <input type="button" value="发送" id="btn"> 用户名：<input type="text" id="textName"/> <script type="text/javascript"> $(function(){ $(‘#btn‘).click(function(){ $.ajax({url:‘ajax.do‘, type:‘POST‘, data:{ name:$(‘#textName‘).val() }, dataType:‘text‘, success:function(data,textStatus){ alert(data); console.log(textStatus) }, error:function(textStatus){ console.log(textStatus) } }) }) }) </script> </body> </html>
2 springmvc处理json数据
a 导入jar包
jackson-annotations-2.7.0.jar
jackson-core-2.7.7.jar
jackson-databind-2.7.8.jar
原文：http://www.cnblogs.com/alloevil/p/6074725.html