Given a string containing just the characters ‘(‘
, ‘)‘
, ‘{‘
, ‘}‘
, ‘[‘
and ‘]‘
,
determine if the input string is valid.
The brackets must close in the correct order, "()"
and "()[]{}"
are
all valid but "(]"
and "([)]"
are
not.
判断给定的字符串是否是合法的成对括号串
class Solution { public: bool isPair(char left, char right){ if(left==‘(‘&&right==‘)‘)return true; if(left==‘{‘&&right==‘}‘)return true; if(left==‘[‘&&right==‘]‘)return true; return false; } bool isValid(string s) { stack<int>st; for(int i=0; i<s.length(); i++){ if(st.empty())st.push(s[i]); else{ char left=st.top(); if(isPair(left,s[i]))st.pop(); else st.push(s[i]); } } return st.empty(); } };
LeetCode: Valid Parentheses [020],布布扣,bubuko.com
LeetCode: Valid Parentheses [020]
原文:http://blog.csdn.net/harryhuang1990/article/details/25973405