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82. Remove Duplicates from Sorted List II

时间:2016-11-27 16:10:46      阅读:239      评论:0      收藏:0      [点我收藏+]

Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.

For example,
Given 1->2->3->3->4->4->5, return 1->2->5.
Given 1->1->1->2->3, return 2->3.

 

/**
 * Definition for singly-linked list.
 * public class ListNode {
 *     int val;
 *     ListNode next;
 *     ListNode(int x) { val = x; }
 * }
 */
public class Solution {
    public ListNode deleteDuplicates(ListNode head) {
        if(head == null || head.next == null) return head;
        ListNode dummy = new ListNode(0);
        dummy.next = head;
        ListNode pre = dummy;
        while(head != null && head.next != null){
           while(head.next != null && head.val == head.next.val){
                head = head.next;
           }
           if(pre.next == head)
                pre = pre.next;
           else
                pre.next = head.next;
           head = head.next;
        }
        return dummy.next;
    }
}

 

82. Remove Duplicates from Sorted List II

原文:http://www.cnblogs.com/joannacode/p/6106352.html

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