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Leetcode: Ransom Note

时间:2016-11-29 09:21:01      阅读:272      评论:0      收藏:0      [点我收藏+]
Given an arbitrary ransom note string and another string containing letters from all the magazines, write a function that will return true if the ransom note can be constructed from the magazines ; otherwise, it will return false.

Each letter in the magazine string can only be used once in your ransom note.

Note:
You may assume that both strings contain only lowercase letters.

canConstruct("a", "b") -> false
canConstruct("aa", "ab") -> false
canConstruct("aa", "aab") -> true

using one array

 1 public class Solution {
 2     public boolean canConstruct(String ransomNote, String magazine) {
 3         int[] mLetters = new int[26];
 4         for (int i=0; i<magazine.length(); i++) {
 5             mLetters[magazine.charAt(i) - ‘a‘]++;
 6         }
 7         for (int j=0; j<ransomNote.length(); j++) {
 8             if (mLetters[ransomNote.charAt(j) - ‘a‘]-- == 0) return false;
 9         }
10         return true;
11     }
12 }

 

Leetcode: Ransom Note

原文:http://www.cnblogs.com/EdwardLiu/p/6112099.html

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