给出一棵二叉树,返回其中序遍历
样例
给出二叉树 {1,#,2,3},
1
2
/
3
返回 [1,3,2].
你能使用非递归算法来实现么?
分析:同前序遍历。
/**
* Definition of TreeNode:
* class TreeNode {
* public:
* int val;
* TreeNode *left, *right;
* TreeNode(int val) {
* this->val = val;
* this->left = this->right = NULL;
* }
* }
*/
class Solution {
/**
* @param root: The root of binary tree.
* @return: Inorder in vector which contains node values.
*/
public:
vector<int> inorderTraversal(TreeNode *root) {
// write your code here
TreeNode *curr=root;
stack<TreeNode *> mystack;
vector<int> res;
while(!mystack.empty()||curr!=NULL)
{
while(curr!=NULL)
{
mystack.push(curr);
curr=curr->left;
}
if(!mystack.empty())
{
curr=mystack.top();
res.push_back(curr->val);
mystack.pop();
curr=curr->right;
}
}
return res;
}
};
用数组指针
/**
* Definition of TreeNode:
* class TreeNode {
* public:
* int val;
* TreeNode *left, *right;
* TreeNode(int val) {
* this->val = val;
* this->left = this->right = NULL;
* }
* }
*/
class Solution {
/**
* @param root: The root of binary tree.
* @return: Inorder in vector which contains node values.
*/
public:
vector<int> inorderTraversal(TreeNode *root) {
// write your code here
TreeNode *curr=root;
TreeNode *mystack[1000];
int top=0;
vector<int> res;
while(top!=0||curr!=NULL)
{
while(curr!=NULL)
{
mystack[top++]=curr;
curr=curr->left;
}
if(top>0)
{
top--;
curr=mystack[top];
res.push_back(curr->val);
curr=curr->right;
}
}
return res;
}
};
原文:http://www.cnblogs.com/lelelelele/p/6115300.html