首页 > 其他 > 详细

[Ramda] allPass, propEq

时间:2016-11-30 07:49:00      阅读:236      评论:0      收藏:0      [点我收藏+]
const needs = [wifi, shower, laundry];

const homes = [{
  name: Home 1,
  wifi: y,
  shower: y,
  laundry: y,
  metro: n,
  balcony: y,
  fireplace: n,
  pool: y
}, {
  name: Home 2,
  wifi: n,
  shower: y,
  laundry: y,
  metro: n,
  balcony: n,
  fireplace: n,
  pool: n
}, {
  name: Home 3,
  wifi: y,
  shower: y,
  laundry: y,
  metro: n,
  balcony: y,
  fireplace: y,
  pool: n
}, {
  name: Home 4,
  wifi: y,
  shower: y,
  laundry: n,
  metro: n,
  balcony: n,
  fireplace: n,
  pool: n
}];

const propMatch = R.curry((toMatch, prop) => R.propEq(prop, toMatch));
const needsCheck = R.map(propMatch(y), needs);
const allNeedsMatch = R.allPass(needsCheck);
const res = R.filter(allNeedsMatch, homes);
console.log(res)

 

[Ramda] allPass, propEq

原文:http://www.cnblogs.com/Answer1215/p/6116157.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!