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[Ramda] allPass, propEq

时间:2016-11-30 07:49:00      阅读:239      评论:0      收藏:0      [点我收藏+]
const needs = [‘wifi‘, ‘shower‘, ‘laundry‘];

const homes = [{
  name: ‘Home 1‘,
  wifi: ‘y‘,
  shower: ‘y‘,
  laundry: ‘y‘,
  metro: ‘n‘,
  balcony: ‘y‘,
  fireplace: ‘n‘,
  pool: ‘y‘
}, {
  name: ‘Home 2‘,
  wifi: ‘n‘,
  shower: ‘y‘,
  laundry: ‘y‘,
  metro: ‘n‘,
  balcony: ‘n‘,
  fireplace: ‘n‘,
  pool: ‘n‘
}, {
  name: ‘Home 3‘,
  wifi: ‘y‘,
  shower: ‘y‘,
  laundry: ‘y‘,
  metro: ‘n‘,
  balcony: ‘y‘,
  fireplace: ‘y‘,
  pool: ‘n‘
}, {
  name: ‘Home 4‘,
  wifi: ‘y‘,
  shower: ‘y‘,
  laundry: ‘n‘,
  metro: ‘n‘,
  balcony: ‘n‘,
  fireplace: ‘n‘,
  pool: ‘n‘
}];

const propMatch = R.curry((toMatch, prop) => R.propEq(prop, toMatch));
const needsCheck = R.map(propMatch(‘y‘), needs);
const allNeedsMatch = R.allPass(needsCheck);
const res = R.filter(allNeedsMatch, homes);
console.log(res)

 

[Ramda] allPass, propEq

原文:http://www.cnblogs.com/Answer1215/p/6116157.html

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