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Leetcode-268 Missing Number

时间:2016-12-16 16:51:17      阅读:175      评论:0      收藏:0      [点我收藏+]

#268.  Missing Number

Given an array containing n distinct numbers taken from 0, 1, 2, ..., n, find the one that is missing from the array.

For example,
Given nums = [0, 1, 3] return 2.

Note:
Your algorithm should run in linear runtime complexity. Could you implement it using only constant extra space complexity?

class Solution {
public:
    int missingNumber(vector<int>& nums) {
        int len=nums.size();
        int ret=0;
        for(int i=0;i<len+1;i++)
        {
            ret^=i;
        }
        for(int i=0;i<len;i++)
        {
            ret^=nums[i];
        }
        return ret;
    }
};

 

Leetcode-268 Missing Number

原文:http://www.cnblogs.com/fengxw/p/6187399.html

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