Given a string s consists of upper/lower-case alphabets and empty space characters ‘
‘, return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s = "Hello World",
return 5.
class Solution {
public:
int lengthOfLastWord(const char *s) {
int i,j;
for(i=strlen(s)-1;i>=0;i--)if(s[i]!=‘ ‘)break;
for(j=i;j>=0;j--)if(s[j]==‘ ‘)break;
return i-j;
}
};
LeetCode OJ:Length of Last Word
原文：http://blog.csdn.net/starcuan/article/details/18852255