在一些项目中可能需要对一段字符串中的单词进行统计，我在这里写了一个简单的demo，有需要的同学可以拿去看一下。
本人没怎么写个播客，如果有啥说的不对的地方，你来打我啊
不说废话了直接贴代码：
实现代码：
/**
* 统计各个单词出现的次数
* @param text
*/
public static void findEnglishNum(String text){
//找出所有的单词
String[] array = {".", " ", "?", "!"};
for (int i = 0; i < array.length; i++) {
text = text.replace(array[i],",");
}
String[] textArray = text.split(",");
//遍历 记录
Map<String, Integer> map = new HashMap<String, Integer>();
for (int i = 0; i < textArray.length; i++) {
String key = textArray[i];
//转为小写
String key_l = key.toLowerCase();
if(!"".equals(key_l)){
Integer num = map.get(key_l);
if(num == null || num == 0){
map.put(key_l, 1);
}else if(num > 0){
map.put(key_l, num+1);
}
}
}
//输出到控制台
System.out.println("各个单词出现的频率为：");
Iterator<String> iter = map.keySet().iterator();
while(iter.hasNext()){
String key = iter.next();
Integer num = map.get(key);
System.out.println(key + "\n\t\t" + num + "次\n-------------------");
}
}
测试代码：
public static void main(String[] args) {
String text = "Welcome welcome to ADempiere, a commons-based peer-production of Open Source ERP Applications. This Wiki is for the global community to contribute and share know-how and domain expertise. We hope you can find as much open information and participate in making it most usable for everyone. This project has a bazaar of Citizens with a Community Council Team which work in theFunctional Team and Technical Team along the Software Development Procedure supported and funded by the foundation ADempiere";
findEnglishNum(text); }
运行结果：
后面还有一些没有全部截下来
本人代码功力不够深厚，如果代码中有什么不对或不好的地方，欢迎各位大神指点！
原文：http://www.cnblogs.com/LFBlog/p/6240906.html