今天复习下servlet的初始化过程,如果xml配置文件没有设置<load-on-startup>大于1的数字</load-on-startup>,
tomcat启动的时候默认是不会初始化servlet的。下面是tomcat开启时,context容器standardContext执行
/** * Load and initialize all servlets marked "load on startup" in the * web application deployment descriptor. * * @param children Array of wrappers for all currently defined * servlets (including those not declared load on startup) */ public void loadOnStartup(Container children[]) { // Collect "load on startup" servlets that need to be initialized TreeMap map = new TreeMap(); for (int i = 0; i < children.length; i++) { Wrapper wrapper = (Wrapper) children[i]; int loadOnStartup = wrapper.getLoadOnStartup(); if (loadOnStartup < 0) continue; Integer key = Integer.valueOf(loadOnStartup); ArrayList list = (ArrayList) map.get(key); if (list == null) { list = new ArrayList(); map.put(key, list); } list.add(wrapper); } // Load the collected "load on startup" servlets Iterator keys = map.keySet().iterator(); while (keys.hasNext()) { Integer key = (Integer) keys.next(); ArrayList list = (ArrayList) map.get(key); Iterator wrappers = list.iterator(); while (wrappers.hasNext()) { Wrapper wrapper = (Wrapper) wrappers.next(); try { wrapper.load(); } catch (ServletException e) { getLogger().error(sm.getString("standardWrapper.loadException", getName()), StandardWrapper.getRootCause(e)); // NOTE: load errors (including a servlet that throws // UnavailableException from tht init() method) are NOT // fatal to application startup } } } }
如果loadOnStartup 小于0就不初始化wrapper(也就是一个servlet)。
TreeMap默认是按key升序排列,所以loadOnStartup设置的值越大就越先初始化。
原文:http://www.cnblogs.com/shapeOfMyHeart/p/6250439.html