统计给定字符串中字母数字的个数

package

javastudy;

import

java.util.HashMap;

public

class CountLetters {

publicstaticvoid main ( String args[] )

    {

        String input =

"016a 8b9c213d20df0G9E";

        String regex =

"(?i)[^a-z]";

        String result = input.replaceAll (regex,

"");

        System.

out.println (result);

        HashMap<String, Integer> map =

new HashMap<String, Integer> ();

for ( int i = 0; i < result.length (); i++ )

        {

            String one = result.charAt (i) +

"";

if (null == map.get (one))

            {

                map.put (one, 1);

            }

else

            {

map.put (one, map.get (one) + 1);

            }

        }

        System.

out.println (map);

        countLetter();

    }

publicstaticvoid countLetter(){

    String str =

"另顶戴枯aslkdfjasf345sdfa";

char[] arr = str.toCharArray();

int number = 0;

int english = 0;

for (char c: arr)

    {   

int i = c + 0;     

if (i > 47 && i < 58)

            number++;   

elseif ((i > 64 && i < 91) || (i > 96 && i < 123))

            english++;

    }

    System.

out.println("原字符串："+str+"数字："+number +"个,"+"字母："+english+ "个");

    }

}

输出结果：

abcddfGE

{f=1, E=1, d=2, G=1, b=1, c=1, a=1}

原字符串：另顶戴枯aslkdfjasf345sdfa数字：3个,字母：14个

统计给定字符串中字母数字的个数

原文：http://www.cnblogs.com/clarke157/p/6280135.html