首页 > 其他 > 详细

006:欧拉项目平方和与和的平方的差

时间:2014-05-23 02:22:37      阅读:408      评论:0      收藏:0      [点我收藏+]

Sum square difference

Problem 6

The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 bubuko.com,布布扣 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

补充两个公式

   bubuko.com,布布扣 证明:倒序相加,

       bubuko.com,布布扣证明:数学归纳法


这都是高中的题目 

给出我的python代码:

n = 100
s1 = n*(n+1)/2 # sum of (1..n)1+2+....+n
s2 = n*(n+1)*(2*n+1)/6 # sum of (1+2**2+3**2+...n**2)
print s1**2-s2


006:欧拉项目平方和与和的平方的差,布布扣,bubuko.com

006:欧拉项目平方和与和的平方的差

原文:http://blog.csdn.net/hackingwu/article/details/26569603

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!