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jQuery -> 获取/设置/删除DOM元素的属性

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Sum square difference

Problem 6

The sum of the squares of the first ten natural numbers is,

12 + 22 + ... + 102 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + ... + 10)2 = 552 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 bubuko.com,布布扣 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

补充两个公式

   bubuko.com,布布扣 证明:倒序相加,

       bubuko.com,布布扣证明:数学归纳法


这都是高中的题目 

给出我的python代码:

n = 100
s1 = n*(n+1)/2 # sum of (1..n)1+2+....+n
s2 = n*(n+1)*(2*n+1)/6 # sum of (1+2**2+3**2+...n**2)
print s1**2-s2


jQuery -> 获取/设置/删除DOM元素的属性,布布扣,bubuko.com

jQuery -> 获取/设置/删除DOM元素的属性

原文:http://blog.csdn.net/feelang/article/details/26575721

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