首页 > 其他 > 详细

Leecode_98_Validate_Binary_Search_Tree

时间:2017-01-27 07:18:19      阅读:235      评论:0      收藏:0      [点我收藏+]

Given a binary tree, determine if it is a valid binary search tree (BST).

Assume a BST is defined as follows:

  • The left subtree of a node contains only nodes with keys less than the node‘s key.
  • The right subtree of a node contains only nodes with keys greater than the node‘s key.
  • Both the left and right subtrees must also be binary search trees.

    Example 1:

        2
       /   1   3
    
    Binary tree [2,1,3], return true.

    Example 2:

        1
       /   2   3
    
    Binary tree [1,2,3], return false.
 1 /**
 2  * Definition for a binary tree node.
 3  * struct TreeNode {
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 8  * };
 9  */
10 class Solution {
11 public:
12     bool isValidBST(TreeNode* root) {
13          return isValidBST(root, LONG_MIN, LONG_MAX);
14     }
15     bool isValidBST(TreeNode *root, long mn, long mx) {
16         if (!root) return true;
17         if (root->val <= mn || root->val >= mx) return false;
18         return isValidBST(root->left, mn, root->val) && isValidBST(root->right, root->val, mx);
19     }
20 };

 

Leecode_98_Validate_Binary_Search_Tree

原文:http://www.cnblogs.com/sarah-zhang/p/6353536.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!