Given two sorted integer arrays nums1 and nums2, merge nums2 into nums1 as one sorted array.
Note:
You may assume that nums1 has enough space (size that is greater or equal to m + n) to hold additional elements from nums2. The number of elements initialized in nums1 and nums2 are m and n respectively.
此题直接上代码吧，比较简单：
public class Solution {
public void merge(int[] nums1, int m, int[] nums2, int n) {
int i =m-1;
int j = n-1;
int k = m+n-1;
while(i>=0||j>=0){
if(i>=0&&j>=0){
if(nums1[i]<nums2[j]){
nums1[k--] = nums2[j--];
}else{
nums1[k--] = nums1[i--];
}
}else if(j>=0){
nums1[k--] = nums2[j--];
}else{
i--;
}
}
}
}
原文：http://www.cnblogs.com/codeskiller/p/6359886.html