题目:
The cows have purchased a yogurt factory that makes world-famous Yucky Yogurt. Over the next N (1 <= N <= 10,000) weeks, the price of milk and labor will fluctuate weekly such that it will cost the company C_i (1 <= C_i <= 5,000) cents to produce one unit of yogurt in week i. Yucky‘s factory, being well-designed, can produce arbitrarily many units of yogurt each week.
Yucky Yogurt owns a warehouse that can store unused yogurt at a constant fee of S (1 <= S <= 100) cents per unit of yogurt per week. Fortuitously, yogurt does not spoil. Yucky Yogurt‘s warehouse is enormous, so it can hold arbitrarily many units of yogurt.
Yucky wants to find a way to make weekly deliveries of Y_i (0 <= Y_i <= 10,000) units of yogurt to its clientele (Y_i is the delivery quantity in week i). Help Yucky minimize its costs over the entire N-week period. Yogurt produced in week i, as well as any yogurt already in storage, can be used to meet Yucky‘s demand for that week.
Input:
* Line 1: Two space-separated integers, N and S.
* Lines 2..N+1: Line i+1 contains two space-separated integers: C_i and Y_i.
Output:
* Line 1: Line 1 contains a single integer: the minimum total cost to satisfy the yogurt schedule. Note that the total might be too large for a 32-bit integer.
Sample Input:
4 5
88 200
89 400
97 300
91 500
Sample Output:
126900
思路:
Code:
1 #include<iostream> 2 #include<algorithm> 3 #include<cstring> 4 5 using namespace std; 6 7 int main() { 8 std::ios::sync_with_stdio(false); 9 int n, s, cost, amount; 10 while(cin>>n>>s) { 11 int mincost = 5010; 12 long long ans = 0; 13 for (int i = 0; i < n; ++i) { 14 cin>>cost>>amount; 15 mincost = min(mincost+s, cost); 16 cost = mincost; 17 ans += cost * amount; 18 } 19 cout<<ans<<endl; 20 } 21 22 return 0; 23 }
原文:http://www.cnblogs.com/robin1998/p/6360825.html