首页 > 其他 > 详细

Construct the Rectangle

时间:2017-02-12 18:44:31      阅读:320      评论:0      收藏:0      [点我收藏+]

For a web developer, it is very important to know how to design a web page‘s size. So, given a specific rectangular web page’s area, your job by now is to design a rectangular web page, whose length L and width W satisfy the following requirements:

1. The area of the rectangular web page you designed must equal to the given target area.

2. The width W should not be larger than the length L, which means L >= W.
3. The difference between length L and width W should be as small as possible.

You need to output the length L and the width W of the web page you designed in sequence.

 

Example:

Input: 4
Output: [2, 2]
Explanation: The target area is 4, and all the possible ways to construct it are [1,4], [2,2], [4,1]. 
But according to requirement 2, [1,4] is illegal; according to requirement 3,  [4,1] is not optimal compared to [2,2]. So the length L is 2, and the width W is 2.

 

Note:

  1. The given area won‘t exceed 10,000,000 and is a positive integer
  2. The web page‘s width and length you designed must be positive integers.

 

 1 public class Solution {
 2     public int[] constructRectangle(int area) {
 3         int[] result = new int[2];
 4         if (area == 0) return result;
 5         
 6         int length = (int) (Math.sqrt(area)) + 1;
 7         while (area % length != 0) length--;
 8         length = Math.max(length, area / length);
 9         
10         int width = area / length;
11         result[0] = length;
12         result[1] = width;
13         
14         return result;
15     }
16 }

 

Construct the Rectangle

原文:http://www.cnblogs.com/amazingzoe/p/6391366.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!