一道sql 关于pivot的面试题

分析：其实它是对时间月份行转列的

表结构设计：

结果：

select Name,moth,ISNULL([01],0) as Value1,ISNULL([02],0) as Value2,ISNULL([03],0) as Value3 from (
select a.Name,CONVERT(varchar(4),moth,120) as moth,CONVERT(varchar(2),moth,100) as moth2,number from Table_Type as a
left join Table_SHUJU as b on a.id=b.id
) as table1 pivot (sum(number) for moth2 in([01],[02],[03])) as table2

效果图：

一道sql 关于pivot的面试题

原文：http://www.cnblogs.com/panmy/p/6411148.html