内容来自廖雪峰的官方网站。
List Comprehensions
1
>>> list(range(1, 3)) [1, 2]
2
>>> L = [] >>> for x in range(1 , 3): ... L.append(x * x) ... >>> L [1, 4]
3
>>> L = [1, 2, 3] >>> L [1, 2, 3] >>> L = [x * x for x in range(1 , 4)] >>> L [1, 4, 9]
4
>>> L = [x for x in range(1 , 100) if x % 2 == 0] >>> L [2, 4, 6, 8, 10, 12, 14, 16, 18, 20, 22, 24, 26, 28, 30, 32, 34, 36, 38, 40, 42, 44, 46, 48, 50, 52, 54, 56, 58, 60, 62, 64, 66, 68, 70, 72, 74, 76, 78, 80, 82, 84, 86, 88, 90, 92, 94, 96, 98]
5
>>> [m + n for m in ‘abc‘ for n in ‘xyz‘] [‘ax‘, ‘ay‘, ‘az‘, ‘bx‘, ‘by‘, ‘bz‘, ‘cx‘, ‘cy‘, ‘cz‘]
运用列表生成式，可以写出非常简洁的代码。
应用举例
1、列出当前目录下的所有文件：
>>> import os
>>> [f for f in os.listdir(‘.‘)] [‘a.exe‘, ‘prog1.cpp‘, ‘prog1.exe‘, ‘Sales_data.h‘, ‘test.py‘, ‘test.py.bak‘, ‘__pycache__‘, ‘新建文件夹‘]
2、将dict转化为list：
>>> d = {‘lucy‘: 7, ‘migo‘: 6, ‘jack‘: 22}
>>> [x + ‘=‘ + str(y) for x,y in d.items()]
[‘migo=6‘, ‘lucy=7‘, ‘jack=22‘]
3、把一个list中所有的字符串变成小写：
>>> L = [‘migo‘, ‘lucy‘, ‘jack‘] >>> [s.upper() for s in L] [‘MIGO‘, ‘LUCY‘, ‘JACK‘]
4、如果list中既包含字符串，又包含整数：
>>> L [‘migo‘, ‘lucy‘, ‘jack‘, 19] >>> [s.upper() for s in L if isinstance(s, str)] [‘MIGO‘, ‘LUCY‘, ‘JACK‘]
原文：http://www.cnblogs.com/xkxf/p/6415771.html