写的sql:
select
to_number(substr(B.年龄, 1, instr(B.年龄, ‘天‘) - 1)) as 年龄, A.病人id, A.主页id
from 病案主页 A, 病人信息 B
where A.病人ID = B.病人ID
and A.主页ID = B.主页ID
and to_number(substr(B.年龄, 1, instr(B.年龄, ‘天‘) - 1)) < 29
and B.年龄 not like ‘%岁%‘
and B.年龄 not like ‘%月%‘
报错:
加上强制规则,运行通过:
select /*+rule*/
to_number(substr(B.年龄, 1, instr(B.年龄, ‘天‘) - 1)) as 年龄, A.病人id, A.主页id
from 病案主页 A, 病人信息 B
where A.病人ID = B.病人ID
and A.主页ID = B.主页ID
and to_number(substr(B.年龄, 1, instr(B.年龄, ‘天‘) - 1)) < 29
and B.年龄 not like ‘%岁%‘
and B.年龄 not like ‘%月%‘
注意:
and to_number(substr(B.年龄, 1, instr(B.年龄, ‘天‘) - 1)) < 29
不能放在最后一个条件,否则也会报错！
本文出自 “菜鸟先飞” 博客，谢绝转载！
oracle to_namber之后报ora-01722:无效数字
原文：http://1826794.blog.51cto.com/1816794/1902500