比较简单没什么好说的：
list_1 = [1,2,3,4,6,3,2,5,7,8,2,1] list_1 = set(list_1) list_1.add(999) list_2 = set([2,3,444,5,1]) print(list_1,list_2) list_3 = [1,3,7] list_3 = set(list_3) list_4 = [2,5,6] list_4 = set(list_4) print(list_1.intersection(list_2)) print(list_1 & list_2) print(list_1.union(list_2)) print(list_2 | list_1) print(list_1.difference(list_2)) print(list_1 - list_2) print(list_1 ^ list_2) print(list_1.issubset(list_2)) print(list_3.isdisjoint(list_4))
输出结果如下：
{1, 2, 3, 4, 5, 6, 7, 8, 999} {1, 2, 3, 444, 5}
{1, 2, 3, 5}
{1, 2, 3, 5}
{1, 2, 3, 4, 5, 6, 7, 8, 999, 444}
{1, 2, 3, 4, 5, 6, 7, 8, 999, 444}
{8, 999, 4, 6, 7}
{8, 999, 4, 6, 7}
{999, 4, 6, 7, 8, 444}
False
True
原文：http://www.cnblogs.com/hjc4025/p/6498263.html