示例代码:
#include<iostream> #include<cmath> #include<cstring> using namespace std; int main() { string hex; long long dec = 0; cin>>hex; int len = hex.length(); for(int i=0 ;i<len;i++) { if(hex[i] >= ‘A‘) { dec += (hex[i] - ‘A‘ + 10)*pow(16,len-1-i); } else { dec += (hex[i] - ‘0‘)*pow(16,len-1-i); } } cout<<dec; return 0; }
如果是将八进制转换为十进制就会相对简单一些,因为八进制中没有英文字母:
#include<iostream> #include<cmath> #include<cstring> using namespace std; int main() { string hex; long long dec = 0; cin>>hex; int len = hex.length(); for(int i=0 ;i<len;i++) { dec += (hex[i] - ‘0‘)*pow(8,len-1-i); } cout<<dec; return 0; }
原文:http://blog.csdn.net/qsyzb/article/details/18888549