示例代码:
#include<iostream>
#include<cmath>
#include<cstring>
using namespace std;
int main()
{
string hex;
long long dec = 0;
cin>>hex;
int len = hex.length();
for(int i=0 ;i<len;i++)
{
if(hex[i] >= ‘A‘)
{
dec += (hex[i] - ‘A‘ + 10)*pow(16,len-1-i);
}
else
{
dec += (hex[i] - ‘0‘)*pow(16,len-1-i);
}
}
cout<<dec;
return 0;
}如果是将八进制转换为十进制就会相对简单一些,因为八进制中没有英文字母:
#include<iostream>
#include<cmath>
#include<cstring>
using namespace std;
int main()
{
string hex;
long long dec = 0;
cin>>hex;
int len = hex.length();
for(int i=0 ;i<len;i++)
{
dec += (hex[i] - ‘0‘)*pow(8,len-1-i);
}
cout<<dec;
return 0;
}原文:http://blog.csdn.net/qsyzb/article/details/18888549