首页 > 其他 > 详细

LeetCode Permutations II

时间:2014-06-29 13:42:21      阅读:326      评论:0      收藏:0      [点我收藏+]
bubuko.com,布布扣
class Solution {
    public:
        vector<vector<int> > permuteUnique(vector<int> &num) {
            vector<vector<int> > result;
            if (num.size() < 1) return result;
            vector<int> path;
            dfs(num, 0, path, result);
        }

        void dfs(vector<int>& dict, int pos, vector<int>& path, vector<vector<int> > &result) {
            int len = dict.size();
            if (pos >= len) {
                result.push_back(path);
                return;
            }
            unordered_set<int> uniques;
            for (int i=pos; i<len; i++) {
                if (i != pos && uniques.count(dict[i]) > 0) continue;
                uniques.insert(dict[i]);
                path.push_back(dict[i]);
                
                int tmp = dict[i];
                dict[i] = dict[pos];
                dict[pos] = tmp;
                
                dfs(dict, pos + 1, path, result);
                path.pop_back();

                tmp = dict[i];
                dict[i] = dict[pos];
                dict[pos] = tmp;
            }
        }
};
bubuko.com,布布扣

 也可以用next_permutation

bubuko.com,布布扣
class Solution {
    public:
    vector<vector<int> > permuteUnique(vector<int> &num) {
            vector<vector<int> > res;
            sort(num.begin(), num.end());
            do {
                res.push_back(num);
            } while (next_permutation(num.begin(), num.end()));
            return res;
        }
        
};
bubuko.com,布布扣

 

LeetCode Permutations II,布布扣,bubuko.com

LeetCode Permutations II

原文:http://www.cnblogs.com/lailailai/p/3755722.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!