一次过,思路是:最大收益可以由所有上升序列差价叠加中获得
1 public class Solution { 2 public int maxProfit(int[] prices) { 3 int profit = 0; 4 if (prices.length == 0 || prices.length == 1) return profit; 5 for (int i = 1; i < prices.length; i++) { 6 if (prices[i] <= prices[i-1]) continue; 7 else { 8 profit += prices[i] - prices[i-1]; 9 } 10 } 11 return profit; 12 } 13 }
Leetcode: Best Time to Buy and Sell Stock II,布布扣,bubuko.com
Leetcode: Best Time to Buy and Sell Stock II
原文:http://www.cnblogs.com/EdwardLiu/p/3758235.html