Given s1, s2, s3, find whether s3 is formed by the interleaving of s1 and s2.
For
example,
Given:
s1 = "aabcc"
,
s2 = "dbbca"
,
When s3 = "aadbbcbcac"
, return
true.
When s3 = "aadbbbaccc"
, return
false.
class Solution { private: string s1,s2,s3; int** able; public: bool isInterleave(string s1, string s2, string s3) { if(s1.length()+s2.length()!=s3.length()) return false; this->s1=s1; this->s2=s2; this->s3=s3; able=new int*[s1.length()+1]; for(int i=0;i<=s1.length();i++) { able[i]=new int[s2.length()+1]; for(int j=0;j<=s2.length();j++) able[i][j]=0; } able[0][0]=1; return isleave(s1.length(),s2.length()); } bool isleave(int index1,int index2) { if(able[index1][index2]!=0) return able[index1][index2]==1; if(index2>0 && isleave(index1,index2-1) && s3[index1+index2-1]==s2[index2-1]) { able[index1][index2]=1; return true; } if(index1>0 && isleave(index1-1,index2) && s3[index1+index2-1]==s1[index1-1]) { able[index1][index2]=1; return true; } able[index1][index2]=-1; return false; } };
Interleaving String,布布扣,bubuko.com
原文:http://www.cnblogs.com/erictanghu/p/3759581.html