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Word Break

时间:2014-05-30 16:10:10      阅读:370      评论:0      收藏:0      [点我收藏+]

Given a string s and a dictionary of words dict, determine if s can be segmented into a space-separated sequence of one or more dictionary words.

For example, given
s = "leetcode",
dict = ["leet", "code"].

Return true because "leetcode" can be segmented as "leet code".

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class Solution {
public:
    bool wordBreak(string s, unordered_set<string> &dict) 
    {
        bool able[s.length()+1];
        able[0]=true;
        for(int i=1;i<=s.length();i++)
        {
            able[i]=false;
            for(int j=0;j<i;j++)
            if(able[j] && dict.find(s.substr(j,i-j))!=dict.end())
            {
                able[i]=true;
                continue;
            }
        }
        
        return able[s.length()];
    }
};
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Word Break

原文:http://www.cnblogs.com/erictanghu/p/3759707.html

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