给定一个字符串,请你将字符串重新编码,将连续的字符替换成“连续出现的个数+字符”。比如字符串AAAABCCDAA会被编码成4A1B2C1D2A。
import java.util.Arrays;
import java.util.Scanner;
public class Test {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String str = scanner.nextLine()+ "*";
char[] c = str.toCharArray();
int count = 1;
//System.out.println(Arrays.toString(c));
for (int i = 1; i < c.length; i++) {
if (c[i] == c[i-1]) {
count++;
} else {
System.out.print(count+""+c[i-1]);
count = 1;
}
}
}
}
原文:http://www.cnblogs.com/zzsaf/p/6675248.html