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两大数相乘 -- javascript 实现

时间:2014-06-02 23:58:16      阅读:597      评论:0      收藏:0      [点我收藏+]
(function(){

var multiply = function(n1,n2){
var nstr1 = n1.toString();
var nstr2 = n2.toString();

var carry = 0;
var ret = "";

var di = 0;
var dj = 0;
var dig = 0.1;
for(var i = nstr1.length - 1 ;i >= 0;i--)
{

var tmp = "";
var di = parseInt(nstr1[i]);
for(var j = nstr2.length - 1;j >= 0;j--)
{
var dj = parseInt(nstr2[j]);
var r = di*dj;

if(r > 10)  {
tmp = r%10;
tmp = r % 10 + tmp;
carry =(r / 10) | 0;
}else{
tmp = r + tmp;
}

}

dig*=10;
if(i < nstr1.length -1)
{
ret = addLarge (ret,tmp * dig);
}
else{
ret = tmp;
}

}

return ret;
}


var addLarge = function(n1,n2){
var carry = 0;
var ret = "";
n1 += "";
n2 += "";

var len = Math.min(n1.length,n2.length);
var sln1 = n1.substr(n1.length - len,n1.length );
var sln2 = n2.substr(n2.length - len,n2.length );

for(var i = len;i > 0; i--)
{

var di = parseInt(sln1[i-1]);
var dj = parseInt(sln2[i-1]);

ret = (carry + di + dj)>= 10 ? ((carry + di + dj) - 10 + ret) : ((carry+di+dj) + ret);

over = ((carry + di + dj) /10 ) | 0;

}

if(n1.length != n2.length)
{
if(n1.length > n2.length){
ret = addLarge(n1.substr(0,n1.length-len),carry.toString()) + ret;
}
else{
ret = addLarge(n2.substr(0,n2.length - len),carry.toString()) + ret;
}

return ret;
}

else{
if(carry> 0)
ret = carry+ ret;

return ret;
}


};

console.log(multiply(3214432444354543,432424));

})();

两大数相乘 -- javascript 实现,布布扣,bubuko.com

两大数相乘 -- javascript 实现

原文:http://blog.csdn.net/csharp25/article/details/27681129

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