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HDUJ 1019 Least Common Multiple

时间:2017-04-29 12:43:41      阅读:255      评论:0      收藏:0      [点我收藏+]

Least Common Multiple

Time Limit: 2000/1000 MS (Java/Others)    Memory Limit: 65536/32768 K (Java/Others)
Total Submission(s): 29480    Accepted Submission(s): 11136


Problem Description
The least common multiple (LCM) of a set of positive integers is the smallest positive integer which is divisible by all the numbers in the set. For example, the LCM of 5, 7 and 15 is 105.

 

Input
Input will consist of multiple problem instances. The first line of the input will contain a single integer indicating the number of problem instances. Each instance will consist of a single line of the form m n1 n2 n3 ... nm where m is the number of integers in the set and n1 ... nm are the integers. All integers will be positive and lie within the range of a 32-bit integer.
 

Output
For each problem instance, output a single line containing the corresponding LCM. All results will lie in the range of a 32-bit integer.
 

Sample Input
2 3 5 7 15 6 4 10296 936 1287 792 1
 

Sample Output
105 10296



#include<stdio.h>
int gcd(int a,int b)
{
	return b==0?

a:gcd(b,a%b); } int main() { int n,a,b,i,m; scanf("%d",&m); while(m--) { scanf("%d%d",&n,&a); for(i=1;i<n;i++) { scanf("%d",&b); a=a/gcd(a,b)*b; } printf("%d\n",a); } return 0; }



HDUJ 1019 Least Common Multiple

原文:http://www.cnblogs.com/ljbguanli/p/6784878.html

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