首页 > 其他 > 详细

Classical Binary Search

时间:2017-05-02 09:10:52      阅读:274      评论:0      收藏:0      [点我收藏+]
public class Solution {
    /**
     * @param nums: An integer array sorted in ascending order
     * @param target: An integer
     * @return an integer
     */
    public int findPosition(int[] nums, int target) {
        // Write your code here
        if (nums == null || nums.length == 0) {
            return -1;
        }
        
        int start = 0;
        int end = nums.length - 1;
        while (start + 1 < end) {
            int mid = start + (end - start) / 2;
            if (nums[mid] == target) {
                return mid;
            } else if (nums[mid] < target) {
                start = mid;
            } else {
                end = mid;
            }
        }
        
        if (nums[start] == target) {
            return start;
        } 
        
        if (nums[end] == target) {
            return end;
        }
        
        return -1;
    }
}

Important point:

1) While (start + 1 < end)

2) int mid = start + (end - start)/2;

3) check both nums[start] and nums[end] at the end 

Classical Binary Search

原文:http://www.cnblogs.com/codingEskimo/p/6794445.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!