匿名函数

1 lambda [arg1 [,arg2,.....argn]]:expression

1 def fun(a, b, opt):
2      print "a =", a
3      print "b =", b
4      print "result =", opt(a, b)
5 
6 fun(1, 2, lambda x,y:x+y)
7 a = 1
8 b = 2
9 result = 3

1 stus = [
2     {"name":"zhangsan", "age":18}, 
3     {"name":"lisi", "age":19}, 
4     {"name":"wangwu", "age":17}
5 ]
6 
#以name排序
7 >>> stus.sort(key = lambda x:x[‘name‘])
8 >>> stus
9 [{‘age‘: 19, ‘name‘: ‘lisi‘}, {‘age‘: 17, ‘name‘: ‘wangwu‘}, {‘age‘: 18, ‘name‘: ‘zhangsan‘}]