[LeetCode] Non-negative Integers without Consecutive Ones 非负整数不包括连续的1

Given a positive integer n, find the number of non-negative integers less than or equal to n, whose binary representations do NOT contain consecutive ones.

Example 1:

Input: 5
Output: 5
Explanation: 
Here are the non-negative integers <= 5 with their corresponding binary representations:
0 : 0
1 : 1
2 : 10
3 : 11
4 : 100
5 : 101
Among them, only integer 3 disobeys the rule (two consecutive ones) and the other 5 satisfy the rule. 

Note: 1 <= n <= 109

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[LeetCode] Non-negative Integers without Consecutive Ones 非负整数不包括连续的1

原文：http://www.cnblogs.com/grandyang/p/6959585.html