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LeetCode --- Balanced Binary Tree

时间:2014-06-08 18:59:00      阅读:375      评论:0      收藏:0      [点我收藏+]

题目链接

题意: 给定一棵二叉树, 判断是否为平衡二叉树, 这里的平衡二叉树指的是:每个结点的左右子树的深度之差不超过1。

附上代码:

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 1 /**
 2  * Definition for binary tree
 3  * struct TreeNode {
 4  *     int val;
 5  *     TreeNode *left;
 6  *     TreeNode *right;
 7  *     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
 8  * };
 9  */
10  class Solution {
11 public:
12     int isBalanced_helper(TreeNode *root, bool &result) {
13         if (root == NULL) return 0;
14         if (!result) return 0;
15         int leftDepth = isBalanced_helper(root->left, result);
16         int rightDepth = isBalanced_helper(root->right, result);
17         if (abs(leftDepth - rightDepth) > 1) result = false;
18         // prevent overwrite of "result"
19         if (!result) return 0;
20         return max(leftDepth, rightDepth) + 1;
21     }
22     
23     bool isBalanced(TreeNode *root) {
24         bool result = true;
25         isBalanced_helper(root, result);
26         return result;
27     }
28 };
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LeetCode --- Balanced Binary Tree,布布扣,bubuko.com

LeetCode --- Balanced Binary Tree

原文:http://www.cnblogs.com/Stomach-ache/p/3776195.html

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