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如何在类中获取request,和网站路径

时间:2017-06-13 23:26:06      阅读:310      评论:0      收藏:0      [点我收藏+]
@RequestMapping(value = "res/testjs")
	public ModelAndView testjs( ModelMap model ) throws Exception {
		String path = resService.getRequestPath();
		model.put("path", path);
		return new ModelAndView("res/testjs");
	}

  上面是调用:

下面是方法:

import javax.servlet.http.HttpServletRequest;
import org.springframework.web.context.request.RequestContextHolder;
import org.springframework.web.context.request.ServletRequestAttributes; 

public String getRequestPath() {
		HttpServletRequest request  = ((ServletRequestAttributes) RequestContextHolder.getRequestAttributes()).getRequest();
		String path =request.getScheme()+"://"+request.getServerName()+":"+request.getServerPort()+"/"+request.getRequestURL()+"/";  
		return path;
	}

  还有web.xml配置监听:

<listener>
        <description>springrequestListener </description>
        <listener-class>org.springframework.web.context.request.RequestContextListener</listener-class>
     </listener>

  效果:

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如何在类中获取request,和网站路径

原文:http://www.cnblogs.com/hoge/p/7004012.html

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