题意：http://acdream.info/problem?pid=1112
Here is Alice and Bob again !
Alice and Bob are playing a game. There are several numbers.First, Alice choose a number n.Then he can replace n (n > 1)with one of its positive factor but not itself or he can replace n with a and b.Here a*b = n and a > 1 and b > 1.For example, Alice can replace 6 with 2 or 3 or (2, 3).But he can’t replace 6 with 6 or (1, 6). But you can replace 6 with 1. After Alice’s turn, it’s Bob’s turn.Alice and Bob take turns to do so.Who can’t do any replace lose the game.
Alice and Bob are both clever enough. Who is the winner?
代码：
/******************************************************
* author:xiefubao
*******************************************************/
#pragma comment(linker, "/STACK:102400000,102400000")
#include <iostream>
#include <cstring>
#include <cstdlib>
#include <cstdio>
#include <queue>
#include <vector>
#include <algorithm>
#include <cmath>
#include <map>
#include <set>
#include <stack>
#include <string.h>
//freopen ("in.txt" , "r" , stdin);
using namespace std;
#define eps 1e-8
#define zero(_) (abs(_)<=eps)
const double pi=acos(-1.0);
typedef long long LL;
const int Max=5000010;
const int INF=1000000007;
int f[300];
bool rem[Max];
int out[Max];
int least[Max];
int p=0;
void init()
{
for(int i=2; i<Max; i++)
if(!rem[i])
{
for(int j=i*2; j<Max; j+=i)
{
if(least[j]==-1)
least[j]=i;
rem[j]=1;
}
least[i]=i;
}
}
int getans(int t)
{
if(f[t]!=-1)
return f[t];
int Rem[1000];
memset(Rem,0,sizeof Rem);
Rem[0]=1;
for(int i=1; i<=t/2; i++)
{
Rem[getans(i)]=1;
Rem[getans(t-i)]=1;
Rem[getans(t-i)^getans(i)]=1;
}
int to=0;
while(Rem[to])to++;
return f[t]=to;
}
int F(int n)
{
if(out[n]!=-1)
return out[n];
int ans=F(n/least[n])+1;
return out[n]=ans;
}
int main()
{
int n;
memset(f,-1,sizeof f);
memset(out,-1,sizeof out);
memset(least,-1,sizeof least);
f[1]=1;
init();
out[1]=0;
for(int i=0; i<20; i++)
F(1<<i);// cout<<i<<" "<<getans(i)<<endl;
while(scanf("%d",&n)==1)
{
int ans=0;
for(int i=0; i<n; i++)
{
int t;
scanf("%d",&t);
ans^=getans(F(t));
}
if(ans)
puts("Alice");
else
puts("Bob");
}
return 0;
}
ACdream群赛1112（Alice and Bob）,布布扣,bubuko.com
原文：http://blog.csdn.net/xiefubao/article/details/29574245