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【HDOJ】1930 And Now, a Remainder from Our Sponsor

时间:2014-06-13 15:11:01      阅读:241      评论:0      收藏:0      [点我收藏+]

简单字符串。

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 1 #include <stdio.h>
 2 
 3 #define MAXLEN 160
 4 
 5 char buf[MAXLEN];
 6 int keys[4], parts[4];
 7 
 8 void getpart(int x) {
 9     int i;
10     for (i=3; i>=0; --i) {
11         parts[i] = x%100;
12         x /= 100;
13     }
14 }
15 
16 int main() {
17     int case_n, n, max, mm;
18     int i, j, k, flag, tmp, len;
19 
20     scanf("%d", &case_n);
21     while (case_n--) {
22         scanf("%d", &n);
23         max = 0;
24         for (i=0; i<4; ++i) {
25             scanf("%d",&keys[i]);
26             if (max < keys[i]) {
27                 max = keys[i];
28                 mm = i;
29             }
30         }
31         len = 0;
32         for (i=0; i<n; ++i) {
33             scanf("%d", &tmp);
34             getpart(tmp);
35             for (j=10000;;++j)
36                 if (j%max == parts[mm])
37                     break;
38             while (1) {
39                 flag = 1;
40                 for (k=0; k<4; ++k) {
41                     if (k == mm) continue;
42                     if (j%keys[k] != parts[k]) {
43                         flag = 0;
44                         break;
45                     }
46                 }
47                 if (flag) break;
48                 j += max;
49             }
50             getpart(j);
51             for (k=1; k<4; ++k) {
52                 if (parts[k] == 27)
53                     buf[len++] =  ;
54                 else
55                     buf[len++] = (char)(parts[k])+A-1;
56             }
57         }
58         while (buf[--len] ==  ) ;
59         buf[len+1] = \0;
60         printf("%s\n", buf);
61     }
62 
63     return 0;
64 }
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【HDOJ】1930 And Now, a Remainder from Our Sponsor,布布扣,bubuko.com

【HDOJ】1930 And Now, a Remainder from Our Sponsor

原文:http://www.cnblogs.com/bombe1013/p/3785046.html

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