首页 > 其他 > 详细

Remove Duplicates from Sorted List II

时间:2014-02-06 16:36:58      阅读:440      评论:0      收藏:0      [点我收藏+]
bubuko.com,布布扣
 1 public class Solution {
 2     public ListNode deleteDuplicates(ListNode head) {
 3         if(head==null || head.next==null)
 4             return head;
 5         ListNode safe = new ListNode(-1);
 6         ListNode pre = head;
 7         ListNode cur = safe;
 8         while(pre!=null){
 9             boolean dul = false;
10             while(pre.next!=null && pre.val == pre.next.val){
11                 pre = pre.next;
12                 dul = true;
13             }
14             if(dul){
15                 pre = pre.next;
16                 continue;
17             }
18             cur.next = pre;
19             pre = pre.next;
20             cur = cur.next;
21         }
22         cur.next = null; //because {1,1}
23         return safe.next;
24     }
25 }
View Code

Given a sorted linked list, delete all nodes that have duplicate numbers, leaving only distinct numbers from the original list.

For example,
Given 1->2->3->3->4->4->5, return 1->2->5.
Given 1->1->1->2->3, return 2->3.

Remove Duplicates from Sorted List II

原文:http://www.cnblogs.com/krunning/p/3538777.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!