Given a linked list, remove the nth node from the end of list and return its head.
For example,
Given linked list: 1->2->3->4->5, and n = 2. After removing the second node from the end, the linked list becomes 1->2->3->5.Note:
Given n will always be valid.
Try to do this in one pass.
使用两个指针进行标记。public ListNode removeNthFromEnd(ListNode head, int n) { ListNode p1 = head; ListNode p2 = head; for(int i = 0; i < n; i ++){ p2 = p2.next; } if(p2 == null){ head = head.next; }else{ while(p2.next != null){ p1 = p1.next; p2 = p2.next; } p1.next = p1.next.next; } return head; }
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Remove Nth Node From End of List
原文：http://blog.csdn.net/u010378705/article/details/31394999