int MOD; inline int mul(int a, int b){ return (long long)a * b % MOD; } int power(int a, int b){ int ret = 1; for (int t = a; b; b >>= 1){ if (b & 1)ret = mul(ret, t); t = mul(t, t); } return ret; } int cal_root(int mod) { int factor[20], num = 0, s = mod - 1; MOD = mod--; for (int i = 2; i * i <= s; i++){ if (s % i == 0){ factor[num++] = i; while (s % i == 0)s /= i; } } if (s != 1)factor[num++] = s; for (int i = 2;; i++){ int j = 0; for (; j < num && power(i, mod / factor[j]) != 1; j++); if (j == num)return i; } }
有用的表格
详细 http://blog.miskcoo.com/2014/07/fft-prime-table
原文:http://www.cnblogs.com/zxhl/p/7220437.html