[USACO5.4]奶牛的电信Telecowmunication
思路:
水题;
代码:
#include <cstdio> #include <cstring> #include <iostream> #include <algorithm> using namespace std; #define maxn 205 #define maxm 20005 #define INF 0x3f3f3f3f int head[maxn],cnt=1,n,m,E[maxm],V[maxm],F[maxm],s,t; int que[maxm<<2],deep[maxn],c1,c2; inline void in(int &now) { char Cget=getchar();now=0; while(Cget>‘9‘||Cget<‘0‘) Cget=getchar(); while(Cget>=‘0‘&&Cget<=‘9‘) { now=now*10+Cget-‘0‘; Cget=getchar(); } } inline void edge_add(int u,int v,int f) { E[++cnt]=head[u],V[cnt]=v,F[cnt]=f,head[u]=cnt; E[++cnt]=head[v],V[cnt]=u,F[cnt]=0,head[v]=cnt; } bool bfs() { memset(deep,-1,sizeof(deep)); int h=0,tail=1,now;que[0]=s,deep[s]=0; while(h<tail) { now=que[h++]; for(int i=head[now];i;i=E[i]) { if(deep[V[i]]<0&&F[i]) { deep[V[i]]=deep[now]+1; if(V[i]==t) return true; que[tail++]=V[i]; } } } return false; } int flowing(int now,int flow) { if(t==now||flow<=0) return flow; int oldflow=0,pos; for(int i=head[now];i;i=E[i]) { if(!F[i]||deep[V[i]]!=deep[now]+1) continue; pos=flowing(V[i],min(flow,F[i])); flow-=pos,oldflow+=pos,F[i]-=pos,F[i^1]+=pos; if(!flow) return oldflow; } if(!oldflow) deep[now]=-1; return oldflow; } int main() { in(n),in(m),in(c1),in(c2),s=c1+n,t=c2; for(int i=1;i<=n;i++) edge_add(i,i+n,1); while(m--) { in(c1),in(c2); edge_add(c1+n,c2,INF); edge_add(c2+n,c1,INF); } int ans=0; while(bfs()) ans+=flowing(s,INF); cout<<ans; return 0; }
AC日记——[USACO5.4]奶牛的电信Telecowmunication 洛谷 P1345
原文:http://www.cnblogs.com/IUUUUUUUskyyy/p/7222957.html