题目链接:https://vjudge.net/problem/UVA-11475
题意:
给你一个串S
你可以在结尾补充任意数量字母,问最少数量使得新串是回文串
题解:
KMP
将S串倒置跑KMP
#include<bits/stdc++.h> using namespace std; #pragma comment(linker, "/STACK:102400000,102400000") #define ls i<<1 #define rs ls | 1 #define pii pair<int,int> #define MP make_pair typedef long long LL; typedef unsigned long long ULL; const long long INF = 1e18+1LL; const double pi = acos(-1.0); const int N = 2e5+10, M = 1e3+20,inf = 2e9; int fail[N]; char a[N],b[N]; int len; void build_fail() { memset(fail,-1,sizeof(fail)); int j = -1; fail[0] = -1; for(int i = 1; i < len; ++i) { while(j!=-1 && b[i] != b[j+1]) j = fail[j]; if(b[j+1] == b[i]) j++; fail[i] = j; } } int kmp() { int j = -1; for(int i = 0; i < len; ++i) { while(j!=-1 && a[i]!=b[j+1]) j = fail[j]; if(b[j+1] == a[i]) j++; } return j+1; } int main() { while(scanf("%s",a)!=EOF) { len = strlen(a); for(int i = 0; i < len; ++i) b[len - i - 1] = a[i]; build_fail(); cout<<a; for(int i = kmp(); i < len; ++i) printf("%c",b[i]); printf("\n"); } return 0; }
UVA 11475 Extend to Palindrome KMP
原文:http://www.cnblogs.com/zxhl/p/7226561.html