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sql复杂的子查询,横向合并结果集

时间:2017-07-29 13:48:47      阅读:539      评论:0      收藏:0      [点我收藏+]

第一个查询的结果集

select * from(
select c.msName,a.msId,c.msPrice, c.msPrice*COUNT(a.msId) as totalMoney,sum(a.msAmount) as totalCount    from BillConsume a right join 
 (select top 1 msTime as startTime,GETDATE() as endTime from BillConsume where DateDiff(dd,msTime,getdate())=0  order by msTime asc) b on a.msTime between b.startTime and b.endTime and a.msId!=0
left join Menus c on c.msId=a.msId   group by a.msId ,c.msName,c.msPrice)s

连接两个结果集的语句

 full join 

第二个查询的结果集

(select sum(t.totalMoney) as allTotalMoney   from (
 select c.msName,a.msId,c.msPrice, c.msPrice*COUNT(a.msId) as totalMoney,sum(a.msAmount) as totalCount  from BillConsume a right join 
 (select top 1 msTime as startTime,GETDATE() as endTime from BillConsume where DateDiff(dd,msTime,getdate())=0  order by msTime asc) b on a.msTime between b.startTime and b.endTime and a.msId!=0
left join Menus c on c.msId=a.msId   group by a.msId ,c.msName,c.msPrice)t)t

连表的条件

on 1=1

 

sql复杂的子查询,横向合并结果集

原文:http://www.cnblogs.com/codeDevotee/p/7255589.html

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