#include<stdio.h>
#include<algorithm>
#include<cmath>
int judge(int a)
{
int j;
for (j = 2; j <= sqrt(a); j++)
{
if (a%j == 0)
return 1;
}
return 0;
}
int main()
{
int i;
for (i = 1; i < 100; i++)
{
if (judge(i) == 0)
printf("%d", i);
}
return 0;
}
输入一个n,输出2到n的详细素数值
原文：http://www.cnblogs.com/liguangsunls/p/7262413.html
