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集合操作

时间:2017-08-06 16:46:28      阅读:247      评论:0      收藏:0      [点我收藏+]

select employee_id, job_id from employees

union all

select employee_id, job_id from job_history;

 

select employee_id, job_id from employees

union

select employee_id, job_id from job_history;   没有重复值 触发排序

 

select employee_id, job_id from employees

intersect

select employee_id, job_id from job_history;

 

select employee_id from employees

minus

select employee_id from job_history;

 

select employee_id, job_id, salary from employees

union all

select employee_id, job_id, null from job_history;

 

select employee_id, job_id, to_char(salary) from employees

union all

select employee_id, job_id, ‘no salary‘ from job_history;

 

集合排序:

select employee_id, job_id, salary from employees

union all

select employee_id, job_id, null from job_history

order by salary;

 

select employee_id, job_id, null from job_history

union all

select employee_id, job_id, salary from employees

order by 3;

集合操作

原文:http://www.cnblogs.com/shan2017/p/7294991.html

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