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OpenCL入门:(二:用GPU计算两个数组和)

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本文编写一个计算两个数组和的程序,用CPU和GPU分别运算,计算运算时间,并且校验最后的运算结果。文中代码偏多,原理建议阅读下面文章,文中介绍了OpenCL相关名词概念。

http://opencl.codeplex.com/wikipage?title=OpenCL%20Tutorials%20-%201  (英文版)

http://www.cnblogs.com/leiben/archive/2012/06/05/2536508.html (博友翻译的中文版)

一、创建工程

按照OpenCL入门:(一:Intel核心显卡OpenCL环境搭建)的创建一个名为OpenCLSum的工程,并且添加一个OpenCLSum.cpp文件,一个OpenCLSum.cl文件(添加时选择添加OpenCL文件)。

二、CPU计算代码

用CPU求两个数组和的代码如下:

void RunAsCpu(
    const float *nums1, 
    const float *nums2, 
    float* sum, 
    const int num)
{
    for (int i = 0; i < num; i++)
    {
        sum[i] = nums1[i] + nums2[i];
    }
}

 

三、GPU计算代码

在cl文件中添加如下代码,
//因为运行这个kernel时需要设置一个线程数目,
//所以每个线程都会调用一次这个函数,只需要使
//用get_global_id获取它的线程id就可以求和了
__kernel void RunAsGpu(
    __global const float *nums1, 
    __global const float *nums2, 
    __global float* sum)
{
    int id = get_global_id(0);
    sum[id] = nums1[id] + nums2[id];
}

 

四、主函数流程

流程请参考本文开始推荐的文章,有详细说明,下面只在注释中简单说明

//计时函数
double time_stamp()
{
    LARGE_INTEGER curclock;
    LARGE_INTEGER freq;
    if (
        !QueryPerformanceCounter(&curclock) ||
        !QueryPerformanceFrequency(&freq)
        )
    {
        return -1;
    }

    return double(curclock.QuadPart) / freq.QuadPart;
}
#define OPENCL_CHECK_ERRORS(ERR)            if(ERR != CL_SUCCESS)                      {                                          cerr                                       << "OpenCL error with code " << ERR        << " happened in file " << __FILE__        << " at line " << __LINE__                 << ". Exiting...\n";                       exit(1);                                   }
int main(int argc, const char** argv)
{
    cl_int error = 0;   // Used to handle error codes
    cl_context context;
    cl_command_queue queue;
    cl_device_id device;

    // 遍历系统中所有OpenCL平台
    cl_uint num_of_platforms = 0;
    // 得到平台数目
    error = clGetPlatformIDs(0, 0, &num_of_platforms);
    OPENCL_CHECK_ERRORS(error);
    cout << "可用平台数: " << num_of_platforms << endl;

    cl_platform_id* platforms = new cl_platform_id[num_of_platforms];
    // 得到所有平台的ID
    error = clGetPlatformIDs(num_of_platforms, platforms, 0);
    OPENCL_CHECK_ERRORS(error);
    //遍历平台,选择一个Intel平台的
    cl_uint selected_platform_index = num_of_platforms;
    for (cl_uint i = 0; i < num_of_platforms; ++i)
    {
        size_t platform_name_length = 0;
        error = clGetPlatformInfo(
            platforms[i],
            CL_PLATFORM_NAME,
            0,
            0,
            &platform_name_length
        );
        OPENCL_CHECK_ERRORS(error);

        // 调用两次,第一次是得到名称的长度
        char* platform_name = new char[platform_name_length];
        error = clGetPlatformInfo(
            platforms[i],
            CL_PLATFORM_NAME,
            platform_name_length,
            platform_name,
            0
        );
        OPENCL_CHECK_ERRORS(error);

        cout << "    [" << i << "] " << platform_name;

        if (
            strstr(platform_name, "Intel") &&
            selected_platform_index == num_of_platforms // have not selected yet
            )
        {
            cout << " [Selected]";
            selected_platform_index = i;
        }

        cout << endl;
        delete[] platform_name;
    }
    if (selected_platform_index == num_of_platforms)
    {
        cerr
            << "没有找到Intel平台\n";
        return 1;
    }
    // Device
    cl_platform_id platform = platforms[selected_platform_index];
    error = clGetDeviceIDs(platform, CL_DEVICE_TYPE_GPU, 1, &device, NULL);
    OPENCL_CHECK_ERRORS(error)

    // Context
    context = clCreateContext(0, 1, &device, NULL, NULL, &error);
    OPENCL_CHECK_ERRORS(error)

    // Command-queue
    queue = clCreateCommandQueue(context, device, 0, &error);
    OPENCL_CHECK_ERRORS(error)

    //下面初始化测试数据(主机数据)
    const int size = 38888888;//大小和内存有关,仅作示例
    float* nums1_h = new float[size];
    float* nums2_h = new float[size];
    float* sum_h = new float[size];
    // Initialize both vectors
    for (int i = 0; i < size; i++) {
        nums1_h[i] = nums2_h[i] = (float)i;
    }
    //初始化设备数据
    const int mem_size = sizeof(float)*size;
    // 标志位表示数据只读,并且从nums1_h和nums2_h复制数据
    cl_mem nums1_d = clCreateBuffer(context, CL_MEM_READ_ONLY | CL_MEM_COPY_HOST_PTR, mem_size, nums1_h, &error);
    OPENCL_CHECK_ERRORS(error)
    cl_mem nums2_d = clCreateBuffer(context, CL_MEM_READ_ONLY | CL_MEM_COPY_HOST_PTR, mem_size, nums2_h, &error);
    OPENCL_CHECK_ERRORS(error)
    cl_mem sum_d = clCreateBuffer(context, CL_MEM_WRITE_ONLY, mem_size, NULL, &error);
    OPENCL_CHECK_ERRORS(error)

    //读取OpenCLSum.cl文件内容

    FILE* fp = fopen("OpenCLSum.cl", "rb");
    fseek(fp, 0, SEEK_END);
    size_t src_size = ftell(fp);
    fseek(fp, 0, SEEK_SET);
    const char* source = new char[src_size];
    fread((void*)source, 1, src_size, fp);
    fclose(fp);

    //创建编译运行kernel函数
    cl_program program = clCreateProgramWithSource(context, 1, &source, &src_size, &error);
    OPENCL_CHECK_ERRORS(error)
    delete[] source;

    // Builds the program
    error = clBuildProgram(program, 1, &device, NULL, NULL, NULL);
    OPENCL_CHECK_ERRORS(error)

    // Shows the log
    char* build_log;
    size_t log_size;
    // First call to know the proper size
    clGetProgramBuildInfo(program, device, CL_PROGRAM_BUILD_LOG, 0, NULL, &log_size);
    build_log = new char[log_size + 1];
    // Second call to get the log
    clGetProgramBuildInfo(program, device, CL_PROGRAM_BUILD_LOG, log_size, build_log, NULL);
    build_log[log_size] = \0;
    cout << build_log << endl;
    delete[] build_log;

    // Extracting the kernel
    cl_kernel run_as_gpu = clCreateKernel(program, "RunAsGpu", &error);
    OPENCL_CHECK_ERRORS(error)


    //运行kernel程序

    // Enqueuing parameters
    // Note that we inform the size of the cl_mem object, not the size of the memory pointed by it
    error = clSetKernelArg(run_as_gpu, 0, sizeof(cl_mem), &nums1_d);
    error |= clSetKernelArg(run_as_gpu, 1, sizeof(cl_mem), &nums2_d);
    error |= clSetKernelArg(run_as_gpu, 2, sizeof(cl_mem), &sum_d);
    OPENCL_CHECK_ERRORS(error)

    // Launching kernel
    size_t global_work_size = size;
    cout << "GPU 运行开始:" << time_stamp() << endl;
    error = clEnqueueNDRangeKernel(queue, run_as_gpu, 1, NULL, &global_work_size, NULL, 0, NULL, NULL);
    cout << "GPU 运行结束:" << time_stamp() << endl;
    OPENCL_CHECK_ERRORS(error)

    //取得kernel返回值
    float* gpu_sum = new float[size];
    clEnqueueReadBuffer(queue, sum_d, CL_TRUE, 0, mem_size, gpu_sum, 0, NULL, NULL);

    cout << "CPU 运行开始:" << time_stamp() << endl;
    RunAsCpu(nums1_h, nums2_h, sum_h, size);
    cout << "CPU 运行结束:" << time_stamp() << endl;

    assert(memcmp(sum_h, gpu_sum, size * sizeof(float)) == 0);

    delete[] nums1_h;
    delete[] nums2_h;
    delete[] sum_h;
    delete[] gpu_sum;
    delete[] platforms;
    clReleaseKernel(run_as_gpu);
    clReleaseCommandQueue(queue);
    clReleaseContext(context);
    clReleaseMemObject(nums1_d);
    clReleaseMemObject(nums2_d);
    clReleaseMemObject(sum_d);
    return 0;

四、运行结果

由于运算比较简单,CPU和GPU几乎没差别,在后续复杂运算中应该是会有差别的。

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五、相关下载

工程下载

六、后续

看了几篇文章后似乎简单使用OpenCL还是不复杂的,OpenCL关键应该在于如何优化性能,如何调用kernel函数,可以将GPU效果最优化。以后的文章一部分涉及OpenCL原理,一部分涉及到更复杂的运算,当然了,博主也是学习阶段,没有练手项目,只能从官方demos中找找了。

OpenCL入门:(二:用GPU计算两个数组和)

原文:http://www.cnblogs.com/Reyzal/p/7392544.html

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