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462. Minimum Moves to Equal Array Elements II

时间:2017-09-02 20:21:41      阅读:241      评论:0      收藏:0      [点我收藏+]

Given a non-empty integer array, find the minimum number of moves required to make all array elements equal, where a move is incrementing a selected element by 1 or decrementing a selected element by 1.

You may assume the array‘s length is at most 10,000.

Example:

Input:
[1,2,3]

Output:
2

Explanation:
Only two moves are needed (remember each move increments or decrements one element):

[1,2,3]  =>  [2,2,3]  =>  [2,2,2]
 1 class Solution {
 2 public:
 3     int minMoves2(vector<int>& nums) {
 4         int len = nums.size();
 5         int sum = 0;
 6         sort(nums.begin(), nums.end());
 7         for (int i = 0;i < len;i++)
 8         {
 9             if (nums[i] != nums[len / 2])
10             {
11                 sum += abs(nums[i] - nums[len / 2]);
12             }
13         }
14         return sum;
15     }
16 };

 

462. Minimum Moves to Equal Array Elements II

原文:http://www.cnblogs.com/wujufengyun/p/7467627.html

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