首页 > 其他 > 详细

LeetCode 554: Brick Wall

时间:2017-09-03 09:44:32      阅读:294      评论:0      收藏:0      [点我收藏+]

The largest number could be n of walls.

class Solution {
    public int leastBricks(List<List<Integer>> wall) {
        if (wall.size() == 0) {
            return 0;
        }
        
        int result = wall.size();
        Map<Integer, Integer> sumMap = new HashMap<>();
        for (List<Integer> row : wall) {
            int sum = 0;
            for (int i = 0; i < row.size() - 1; i++) {
                sum += row.get(i);
                sumMap.put(sum, sumMap.getOrDefault(sum, 0) + 1);
            }
        }
        
        for (int value : sumMap.values()) {
            result = Math.min(wall.size() - value, result);
        }
        return result;
    }
}

 

LeetCode 554: Brick Wall

原文:http://www.cnblogs.com/shuashuashua/p/7468684.html

(0)
(0)
   
举报
评论 一句话评论(0
关于我们 - 联系我们 - 留言反馈 - 联系我们:wmxa8@hotmail.com
© 2014 bubuko.com 版权所有
打开技术之扣,分享程序人生!